Can someone help expalin this
problem a little better for me, I would really appreciate it.
1. (6 points) Consider the cross: Hfr: neo pro- met+ gal+man-lys- x F: neo pro- met- gal+man+ lys+ where the genetic map is shown below (the < indicates the Origin of transfer in the Hfr strain) pro al neo man met Circle the media below which would select for the most exconjugants. a) Minimal media + neomyciın b) Minimal media+ proline c) Minimal media + galactose d) Minimal media+ proline galactose e) Minimal media+ neomycin + mannose f) Minimal media + galactose + neomycin g) Minimal media + lysine +methionine + proline h) Minimal media+ neomycin lysine +proline i) Minimal media +methionine + galactose +lysine j) Minimal media + neomycin + mannose + methionine + lysine +proline k) Minimal media + neomycin + galactose +methionine + lysine 1) Minimal media +galactose + ncomycin + proline+ lysine + methionine m) None of these above Can someone please explain to me how to do this problem, the answer is in red
